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Suppose an object is thrown with the same initial velocity and direction on Earth and on the Moon, where the acceleration due to gravity is one-sixth its value on Earth. How will vertical velocity, time of fight, maximum height, and horizontal distance change?

I would appreciate if they were numerical values like doubles or triples. Thank you

2 Answers

6 votes

Let's call

g = acceleration on earth

g '= acceleration on the moon.

We know that:


g'= (1)/(6)g

1. The formula for vertical velocity on earth is:


V_y = V_0sin(\theta) - gt

On the moon, we have:


V_y'= V_0sin(\theta) - (1)/(6)gt


V_y -V_y'= V_0sin(\theta) - gt - V_0sin(\theta) + (1)/(6)gt


Vy -Vy'= (1)/(6)gt -gt


Vy -Vy'= gt((1)/(6) -1)


Vy'= Vy + gt((5)/(6))

The vertical speed on the moon is greater than on earth by a factor of gt (5/6)

2. The formula for the time of flight on earth is:


t_v = 2(V_0sin(\theta))/(g)

On the moon it is:


t_v'= 2(V_0sin(\theta))/(((1)/(6)g))


t_v'= 12(V_0sin(\theta))/(g)


(t_v')/(t_v) = (12)/(2)


t_v'= 6t_v

The time of flight on the moon is 6 times greater than on earth.

3. The maximum height on earth is:


h = (V_0^2sin^2(\theta))/(2g)

On the moon:


h' = (V_0^2sin^2(\theta))/(2((1)/(6)g))\\\\h' = 3(V_0^2sin^2(\theta))/(g)

So:


(h')/(h) = ([3(V_0^2sin^2(\theta))/(g)])/([(V_0^2sin^2(\theta))/(2g)])


h'= 6h

The maximum height on the moon is 6 times greater than on earth.

4. On earth, the horizontal distance traveled is equal to:


r_x = V_0cos(\theta)t_v\\\\r_x'= V_0cos(\theta)(6t_v)\\\\(r_x')/(r_x) = 6\\\\r_x'= 6r_x\\\\

The horizontal distance traveled on the moon is 6 times greater than that of the earth.

User Wgm
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6.8k points
2 votes

As we know that

Time of flight is given by


T = (2vsin\theta)/(g)

Vertical height


H = (v^2sin^2\theta)/(2g)

Horizontal range


R = (v^2sin2\theta)/(g)

vertical speed


v_y = vsin\theta

now we can see all factors except vertical speed depends on gravity inversely

So here we can say that

Range on moon will increase by 6 times

Maximum vertical height increased by 6 times

Time of flight increased by 6 times

as all above depends inversely on gravity

vertical speed remains unchanged as it is independent of gravity

User Steve Smith
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5.9k points