Question

Find the vertical asymptote for y=x^2-5x/x^2-x-2

Answer 1

vertical asymptote at x=2 and x=-1

Explanation:

`y= (x^2-5x)/(x^2-x-2)`

To find out vertical asymptote we set the denominator =0 and solve for x

`x^2 - x - 2=0`

now factor left hand side

find out two factors whose product is -2 and sum is -1

-2 times 1 = -2

-2+1 = -1

(x-2)(x+1) =0

x-2 =0 so x= 2

x+1 =0 so x=-1

vertical asymptote at x=2 and x=-1