Question

Seth wishes to determine the height of a building. In a large, level parking lot next to the building, Seth measures a signpost as 3.25m high. He backs up from the signpost – away from the building – until the top of the sign is just within his range of view as he looks at the top of the building. He marks the spot where he is standing. Seth then measures the distances as shown in the illustration below. Finally, Seth determines his eye level is at a height of 1.72m above the ground. To the nearest hundredths place, what did Seth find or the height of the building?

Answer 1

CD is height of Building which is 43.75 m

Explanation:

Please look at the attachment for the figure labels

BP=OB -OP

BP=3.25-1.72

BP=1.53

Now, proportion states that two ratios or fractions are equal.

`(BP)/(AP)=(CE)/(EP)`

`(1.53)/(4.16)=(CE)/(114.30)`

`CE=(1.53\cdot 114.30)/(4.16)`

`CE=42.03`

And CD=CE+ED

ED=AQ

CD=42.03+1.72=43.75

CD is height of Building which is 43.75 m