Question

What is the value of:

Answer 1

Explanation:

`\log(x) = - 1`

`\log(y) = 6`

`\log(z) = 2`

`\:`

`= \log( \frac{ {x}^(3)y }{ {z}^(2) } )`

`= \log( {x}^(3) * y / {z}^(2) )`

`= \log( {x}^(3) ) + \log(y) - \log( {z}^(2) )`

`= 3 \log(x) + \log(y) - 2 \log(z)`

`= 3.( - 1) + 6 - 2`

`= - 3 + 6 - 2`

`= 1`