Answer:
option-B
Explanation:
we have to find probability for 5 or more
Calculation of p(5):
number of editorials having 5 responses is 16
total number of editorials =200
so, we can find probability
![p(5)=(16)/(200)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ibebu4p2jtoz7alyv8nyl40alz304aqe00.png)
![p(5)=(2)/(25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ufann3yq5hs81k8pvbxgotcy3h9971c0jy.png)
Calculation of p(=>6):
number of editorials having 6 or more responses is 6
total number of editorials =200
so, we can find probability
![p(=>6)=(6)/(200)](https://img.qammunity.org/2020/formulas/mathematics/high-school/bigjet3qfxq8vgj5j8clzr51ycu6ytfrhl.png)
![p(=>6)=(3)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/v7pv13aaf07yim6jr60yadbjws3wtz4xpp.png)
Calculation of p(=>5):
we can use formula
p(>=5)=p(5)+p(=>6)
we can plug values
![p(=>5)=(2)/(25)+(3)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zq8pqwbpc6yd1wh1a2jyhi4dlx761uqyw3.png)
![p(\geq5 )=(11)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/oo8z65hf0b5w2slhhwpmo1ctc4qurudl9s.png)
![p(\geq5 )=0.11](https://img.qammunity.org/2020/formulas/mathematics/high-school/cj7lln4p2f193ok0gyde2wdygjlepyfrw0.png)
so, answer is option-B