Question

I need help to find the sequence. Please Help

Answer 1

t1 = 7

t2= 10

t3 = 13

tn+1 = 3n+7

tn+1 -tn =3

Explanation:

tn = 3n+4

Let n =1

t1 = 3(1) +4 = 7

Let n =2

t2 = 3(2) +4 = 6+4 = 10

Let n=3

t3 = 3(3)+4 = 9+4 = 13

Let n=n+1

tn+1 = 3(n+1)+4 = 3n+3+7 = 3n+7

Now we need to find t n+1 - tn

tn+1 -tn = 3n+7 - (3n+4)

Distribute the minus sign

= 3n+7-3n-4

3