Answer:
82.49 percent were at least high school graduates.
Explanation:
We have been given that at 1950 x=0
and at 1960 x=10
And following this pattern at 2000 x=50
So, we have coordinates:
(0,34.7) and (50,87.8) for two point form we will find a function:
Using:
![y-y_1=(y_2-y_1)/(x_2-x_1)\cdot (x-x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dg9e4szsfp35d022qz32sk26odbgj86o92.png)
Substituting the values in the formula we get:
![y-34.7=(87.8-34.7)/(50-0)(x-0)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ri03whqlr5lgy7vuj95k0hpwa1iv5mzfx.png)
![y-34.7=1.062(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x7usps6hylisisxbhxjheqg7nvw5da01j1.png)
y=1.062 x+34.7 is the linear function
(b) Now, we need to find the value at x= 1995 which will be equal to 45 according to the pattern followed
Put x=1995 in the function above we get:
y =1.062(45)+34.7
y=82.49 percent were at least high school graduates.