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What is y=8/3x-68/3 in standard form?
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What is y=8/3x-68/3 in standard form?

User Rolandl
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1 Answer

3 votes

Answer:

The standard form of this equation is -8x + 3y = -68

Explanation:

In order to find this, first solve for the constant.

y = 8/3x - 68/3

-8/3x + y = -68/3

Now we multiply by 3 to get them all equal to integers.

-8x + 3y = -68

User Boude
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