Answer:
1.9
Explanation:
The above is direct and inverse variation.
A = kB/C -----------(1)
A=12
B = 3
C= 2
substitute A, B and C into equation (1).
12 = K × 3/2
12 = 3k/2
12×2 = 3k
3K = 24
dividing bothsides by 3
3K/3 = 24/3
K = 8
substitute K = 8 into equation (1)
A = 8B /C --------------(2)
Equation (2) is the equation connecting
A,B and C.
Finding B when A = 10 and C = 1.5
10 = 8B / 1.5
10× 1.5 = 8B
15 = 8B
Dividing bothsides by 8 :
B = 15/8
B = 1.875
B = 1. 9 ( approximately)