Question

High-speed stroboscopic photographs show that the head of a 214 g golf club is trav- eling at 36.7 m/s just before it strikes a 45.9 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 26.9 m/s. Find the speed of the golf ball immediately after impact. Answer in units of m/s.

Answer 1

v = 45.7 m/s

Step-by-step explanation:

It is given that the head of a golf club has a mass of 214 g and is travelling at 36.7 m.s before the impact with a golf ball which has a mass of 45.9 g and is at rest on a tee.

After the club hits the ball, its speed decreases to 26.9 m/s and we are to determine the speed of the golf ball after the impact.

So, the initial momentum (
`P_i`) = 36.7 * 214 = 7853.8 g; and

the final momentum (
`P_f`) = 45.9 * v + 214 * 26.9

Since (
`P_i`) = (
`P_f`),

7853.8 = 45.9v + 5756.6

45.9v = 2097.2

v = 45.7 m/s