#7
Given that an electron revolves in a circle and the essential centripetal force is given as
![F = 4.60 * 10^(-14)N](https://img.qammunity.org/2020/formulas/physics/middle-school/lydyjmdq88zzys79plbho9bvhb79j5yx6q.png)
now we need to find its speed
so we know that this force is given as
![F = (mv^2)/(R)](https://img.qammunity.org/2020/formulas/physics/middle-school/vaah5d2ycy120qv4kqj10menu2ur9108en.png)
![4.60 * 10^(-14) = (9.11 * 10^(-31) v^2)/(2 * 10^(-2))](https://img.qammunity.org/2020/formulas/physics/middle-school/m5neomoyvl8vd98bkh5uhmyrcj4mlkaw9t.png)
![v^2 = 1.01 * 10^(15)](https://img.qammunity.org/2020/formulas/physics/middle-school/rvtefeozvtslog9om02mtung3h4cm6uyru.png)
![v = 3.18 * 10^7 m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/tdab3a3aw63jzrzn5wwgx7mrwd3m6z79ye.png)
#8
Here the force due to earth on satellite is the centripetal force to revolve around earth
so we can say that force due to earth is given as
![F = (mv^2)/(R)](https://img.qammunity.org/2020/formulas/physics/middle-school/vaah5d2ycy120qv4kqj10menu2ur9108en.png)
we know that
![m = 2.7 * 10^3 kg](https://img.qammunity.org/2020/formulas/physics/middle-school/presw7b0nov3z08ckbtfpd7frvsz70v1uz.png)
![v = 4.7 * 10^3 m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/jhp8lqk9pbrw2gtusfeof0l172i19fa87y.png)
![R = 1.8 * 10^7 m](https://img.qammunity.org/2020/formulas/physics/middle-school/4hnvj3z1zybqre52wzwh6lexelz69eg8cl.png)
now from above equation we have
![F = ((2.7 * 10^3)(4.7 * 10^3)^2)/(1.8 * 10^7)](https://img.qammunity.org/2020/formulas/physics/middle-school/s55stnks8u6hoopsha7i1dv4lef3ilpgz3.png)
![F = 3313.5 N](https://img.qammunity.org/2020/formulas/physics/middle-school/u1qq7jz69808lwp9jm13rbo84ec1ybtlcf.png)