Answer:
x = 3, y = -1
Explanation:
![\left \{ {{4x-3y=15} \atop {2x+2y=4}} \right.](https://img.qammunity.org/2020/formulas/mathematics/high-school/cu2qedk8r1uyxpo09whltp1jn1wwjo19mb.png)
To solve this, we will eliminate x. In order to do this, we must multiply the bottom equation by 2:
![\left \{ {{4x-3y=15} \atop {2(2x+2y=4)}} \right. \\\\\left \{ {{4x-3y=15} \atop {4x+4y=8}} \right.](https://img.qammunity.org/2020/formulas/mathematics/high-school/7f2vbarrmvm7c4yzwis8o152s1s4a944z1.png)
To eliminate x, we will subtract the bottom equation from the top one:
![\left \{ {{4x-3y=15} \atop {-(4x+4y=8)}} \right. \\\\-3y-4y=15-8\\\\-7y=7](https://img.qammunity.org/2020/formulas/mathematics/high-school/1vta4d93d810811d3yv0i20to5pn6ekrqc.png)
Divide both sides by -7:
-7y/-7 = 7/-7
y = -1
Substitute this into the first equation:
4x-3(-1) = 15
4x--3 = 15
4x+3 = 15
Subtract 3 from each side:
4x+3-3 = 15-3
4x = 12
Divide both sides by 4:
4x/4 = 12/4
x = 3