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What mass of oxygen would form from 2.30 moles of water?

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Answer : The mass of oxygen will be, 36.8 grams

Solution : Given,

Moles of water = 2.30 moles

Molar mass of
O_2 = 32 g/mole

First we have to calculate the moles of oxygen.

The balanced chemical reaction will be,


2H_2O\rightarrow 2H_2+O_2

From the balanced reaction we conclude that

2 moles of water decomposes to give 1 mole of
O_2

2.30 moles of water decomposes to give
(2.3)/(2)=1.15 moles of
O_2

Now we have to calculate the mass of oxygen.


\text{Mass of }O_2=\text{Moles of }O_2* \text{Molar mass of }O_2


\text{Mass of }O_2=(1.15moles)* (32g/mole)=36.8g

Therefore, the mass of oxygen will be, 36.8 grams

User Saadnib
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