Question

Think of one leg of a right triangle is 21' and the length of the hypothenuse is 29' what is the length of the other leg

Answer 1

length of other leg = 20'

Explanation:

Given:

One leg of triangle let it be base of triangle = 21'

Hypotenuse = 29'

To Find:

Third leg =perpendicular = ?

Solution:

Given is a right angled triangle with two of its sides given to us

We have Pythagoras theorem for right angled triangle and according to it

Pythagoras theorem is

for a right angled triangle

(hyp) ² = (perp)²+(base)²

We have the values of hyp and base

putting them in the equation we get

(29) ² = (perp) ²+(21) ²

841 = (perp) ² + 441

subtracting 441 from both sides we get

841 - 441 = (perp) ² + 441 - 441

400 = (perp)²

or

(perp) ²=400

Taking square root of both sides

`\sqrt{(perp)^(2) }=√(400)`

it gives us

perp = ± 20'

As it is length and it can not be negative so

perp = 20'

or

length of other leg = 20'