Question

The total pressure of a mixture of three gases in container is 3,345 mmHg. Gas #1 has a pressure of 988 mmHg and Gas #2 has a pressure of 1289 mmHg. What is the pressure of gas #3?

Answer 1

According to Dalton's law of partial pressure: The pressure exerted by a mixture of gases is sum partial pressure of each gas exert on the container.

`P_(total)=p_(1)+p_(2)+p_(3).......`

Here we have mixture of three gases so the total pressure of three gases will be sum of their individual or partial pressures

`P_(total)=p_(1)+p_(2)+p_(3)=3345=988+1289+p_(3)`

Therefore the partial pressure of third gas will be

`p_(3)=3345-(988+1289)=1068mmHg`

The pressure of gas#3 is 1068mmHg