Question

Which of the following correctly describes the roots of the quadratic equation shown below?

x^2-6+12=0

2 complex roots (My guess)

2 irrational roots

2 rational roots

1 rational (double) roots

Answer 1

Explanation:

Solving gives you an problem with an i in it when using quadratic. Therefore it is a + and - and are complex. 2 complex roots

Answer 2

2 complex roots

Explanation:

To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.

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`b^2-4ac>0` yields 2 real roots

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`b^2-4ac=0` yields 1 real root

• [tx]b^2-4ac<0[/tex] yields no real roots

`x^2-6x+12=0` where a=1, b=-6, and c=12

`b^2-4ac=(-6)^2-4(1)(12)=36-48=-12<0)` has no real roots