Question

A block of mass 2.0kg resting on a smooth horizontal plane is acted upon simultaneously by two forces, 10N due to north and 10n due to east. the magnitude of the acceleration produced by the forces on the block is what

Answer 1

In triangle ABC

AB = hypotenuse = Net force = R

Using Pythagorean theorem

`AB=\sqrt{AC^(2)+BC^(2)}`

`R=\sqrt{10^(2)+10^(2)}`

R = 14.1 N

m = mass of the block = 2.0 kg

a = acceleration of the block = ?

Magnitude of the acceleration is given as

`a=(R)/(m)\\`

`a=(14.1)/(2)\\`

a = 7.05 m/s²