Question

Hardy Weinberg problems

can someone check my answers
6. Consider that the gene pool of a certain animal population contains just 2 alleles for the gene that controls hair color. If the frequency of the H allele is 0.45, what percent of the population is homozygous for H (i.e. HH)?Round your answer to the nearest tenth of a percent (i.e. 10.7%). Do not include the "%" sign in the box.
a. 20.3
7. If the frequency of the aa genotype is 34%, what is the frequency of the AA genotype? Assume that there are only two alleles (i.e. a and A).Round your answer to the nearest tenth of a percent (i.e. 10.7%). Do not include the "%" sign in the box.
a. 17.4
8. Assume that in a certain population of giraffes, dark brown spots are dominant to light brown spots. If the frequency of dark brown giraffes is 65%, what is the frequency of the dark brown allele? Hint: the frequency that is provided is the frequency of a specific phenotype (i.e. not a genotype frequency).Round your answer to the nearest tenth of a percent (i.e. 10.7%). Do not include the "%" sign in the box.
a. 19.4

Answer 1

1. If we have a gene with two alleles, for example H (dominant allele) and h (recessive allele) than according the HW equilibrium (p2+2pq+q2=1, p+q=1)

p is the frequency of the allele H (),

q is the frequency of the allele h.

p2 is the frequency of dominant homozygous,

q2 is frequency of the recessive homozygous and

2pq is frequency of the heterozygous.

So, if p=0.45, than p2=0.2025=20.3%

2. If the gene is with two alleles, A (dominant) and a (recessive) than according the HW equilibrium (p2+2pq+q2=1, p+q=1)

p is the frequency of the allele A,

q is the frequency of the allele a.

p2 is the frequency of dominant homozygous (AA),

q2 is frequency of the recessive homozygous (aa) and

2pq is frequency of the heterozygous (Aa).

If the frequency of the aa genotype is 34%, than q2=0.34, q=0.58, p=1-0.58=0.42

p2=0.176=17.6%

3. If the gene for giraffe spots is with two alleles, A for dark brown(dominant) and a for light brown (recessive) than according the HW equilibrium (p2+2pq+q2=1, p+q=1):

p is the frequency of the allele A (dark brown allele),

q is the frequency of the allele a (light brown allele).

p2 is the frequency of dominant homozygous (AA-dark),

q2 is frequency of the recessive homozygous (aa-light) and

2pq is frequency of the heterozygous (Aa-dark).

If the frequency of dark brown giraffes is 65%, p2+2pq=0.65, than q2= 1-0.65=0.35

q=0.59, p=0.41=41%