Question

300 mL of salt solution contains 6.5 grams of NaCl (molecular mass of sodium chloride is 58.44 ul.

What is its molarity?

Answer 1

.371 M

Step-by-step explanation:

Molarity, M, is calculated as moles solute/ liters of solvent

6.5 gms of salt is 6.5 / 58.44 = .111225 moles

300 ml = .3 L

.111225 moles / .3 L = .371 M

Answer 2

M=n/V

M=(6.5/58.44) mol : 0.3 L

M=0.371