Answer:
Let W be the width of the rectangle.
Let L be the length of the rectangle.
The length is 3 cm more than twice its width. Therefore:
L = 2W + 3
The perimeter of the rectangle is 34 cm. Therefore:
2W + 2L = 34
We can substitute the value of L from the first equation into the second:
2W + 2(2W + 3) = 34
Distributing the 2 on the right:
2W + 2*2W + 2*3 = 34
2W + 4W + 6 = 34
6W + 6 = 34
Subtracting 6 from both sides:
6W + 6 - 6 = 34 - 6
6W = 28
Dividing both sides by 6:
or,
W = 4 and 2/3
We can substitute this value of W back into the first equation
to find the value of L:
L = 2*W + 3
or,
L = 9 and 1/3 + 3 so,
L = 12 and 1/3