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72 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

3 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!!

11 MINUTES 11 SECONDS TO ANSWER!!!!!!!!!!!!!!!!!!!!!!!!!

72 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 3 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!! 11 MINUTES-example-1
72 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 3 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!! 11 MINUTES-example-1
72 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 3 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!! 11 MINUTES-example-2
72 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 3 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!! 11 MINUTES-example-3
User Rish K
by
8.4k points

2 Answers

0 votes

Answer:

736^2 1467^2

2. 2PQ = <-16,2> magnitude =sqrt(260)

3.The center is (0,0)

The vertices are at (0,±25)

The foci are at (0, ±20)

Explanation:

User Weigan
by
8.6k points
6 votes

Answer:

1. x^2 y^2

----------- + ----------- = 1

736^2 1467^2


2. 2PQ = <-16,2> magnitude =sqrt(260)

3.The center is (0,0)

The vertices are at (0,±25)

The foci are at (0, ±20)

Explanation:

1. Equation for an ellipse

x^2/a^2+ y^2/b^2 = 1

a is the distance from the center to the ellipse

a = the radius of the moon plus the shorter distance of the satellites orbit

a = 567+ 169

=736

b =the radius of the moon plus the longer distance of the satellites orbit

b = 567+ 900

b =1467

x^2 y^2

----------- + ----------- = 1

736^2 1467^2


2. P( -5,5) Q (-13,6)

PQ = Q-P

= (-13--5, 6-5)

= (-13+5,1)

= (-8,1)

2 PQ = 2* (-8,1)

= (-16,2)

magnitude = sqrt((-16)^2 +2^2)

= sqrt(256+4)

=sqrt(260)


3. x^2/225 + y^2/625 = 1

is of the form (x-h)^2/a^2 + (y-k)^2/b^2 =1

where (h,k) is the center

The center is (0,0)

The vertices are at (±b,0) since b>a

sqrt(b^2) = sqrt(625) = 25

The vertices are at (0,±25)

The foci are at (0, ±c)

where b^2= a^2 +c^2

625^2 = 225+c^2

Subtract 225 from each side

400 = c^2

sqrt(c^2) = sqrt(400)

c = 20

The foci are at (0, ±20)

User Surreal
by
8.6k points

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