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The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y. y=3 x10^8/x what are the wavelengths for X-rays within frequency 3 x 10^18

The inverse variation equation shows the relationship between wavelength in meters-example-1
User Paullo
by
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2 Answers

3 votes

Answer:


1*10^(-10) m

Explanation:

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y.


y=(3*10^8)/(x)

x is the wavelength and y is the frequency

we are given with frequency 3*10^18

we plug in 3*10^18 for y


3*10^(18)=(3*10^8)/(x)

cross multiply it


3*10^(18)* x= 3*10^8

divide by 3*x10^18 on both sides


x=(3*10^8)/(3*10^(18))


x=(1)/(10^(10))

or x= 1*10^-10 m


User Jmacedo
by
6.2k points
5 votes

Answer:

First option: 1*10^(-10) m

Explanation:

y=3*10^8/x

Wavelength (in meters): x=?

Frequency: y=3*10^18

Replacing y by 3*10^18 in the equation:

3*10^18=3*10^8/x

Solving for x: Cross multiplication:

3*10^18*x=3*10^8

Dividing both sides of the equation by 3*10^18:

3*10^18*x/(3*10^18)=3*10^8/(3*10^18)

Simplifying:

x=10^8/10^18

x=10^(8-18)

x=10^(-10)

x=1*10^(-10) m

User Pawandeep
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5.9k points