Question

Given (-3, 1) and (3,-3). The slope of the line is _______ . The equation of the line is ___________ .

-2/3
2/3
1/3
y=-2/3x-1
y=2/3x+1

Answer 1

-2/3

y= -2/3x-1

Explanation:

Slope is found from

m = (y2-y1)/(x2-x1)

= (-3-1)/(3--3)

= -4/(3+3)

= -4/6

= -2/3

The equation of the line can be found by using point slope form

y-y1=m(x-x1)

y-1 = -2/3(x--3)

y-1 = -2/3(x+3)

Distribute the -2/3

y-1 = -2/3x -2

Add 1 to each side

y-1+1 = -2/3x-2+1

y = -2/3x-1

Answer 2

-2/3

y=-2/3 x -1

Explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

`m=(y_2-y_1)/(x_2-x_1)=(-3-1)/(3--3)=(-4)/(3+3)=(-4)/(6)=(-2)/(3)`

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-1)=-2/3(x--3)

y-1=-2/3(x+3)

y=-2/3 x -6/3 +1

y=-2/3 x -1