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How much heat energy is added to 5 grams of water if the initial temperature was 50°C and the final temperature was 60°C? (The specific heat of water is 4.18 J/g°C)

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Energy added = mass*specific heat* rise in temperature.

= 5 * (60-50) * 4.18

= 50*4.18

= 209 J (answer).

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