Answer:
2120 books
Explanation:
Let the number of books be
![x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k3ozza40nv61jy1offmxaxutrb6y1c3ly5.png)
- For the first method, we can write the cost equation as:
Cost =
![47,642+9.25x](https://img.qammunity.org/2020/formulas/mathematics/high-school/446dcbl4rzder0xr4emnhgdcrxpx6d1pv0.png)
- For the second method, we can write the cost equation as:
Cost =
![23,792+20.50x](https://img.qammunity.org/2020/formulas/mathematics/high-school/j92i1fzd167rqp99l612lln4vw4qi35gqp.png)
Since we want cost to be same, we equate the 2 equations of cost and solve for x, the number of books, to get our answer:
![47,642+9.25x=23,792+20.50x\\47,642-23,792=20.50x-9.25x\\23,850=11.25x\\x=(23,850)/(11.25)\\x=2120](https://img.qammunity.org/2020/formulas/mathematics/high-school/igm8d0m55o0ld7cdki9lzuq10jkp78eosq.png)
The cost for both methods will be same for 2120 books