The volume of a hexagonal pyramid is represented by the expression 12x 3 cubic inches and its height is 24 inches. The area of the hexagonal base is(blank) x 3 square inches.

Question

asked May 19, 2020 191k views

2 Answers

Fredarin · Answer 1 · 2020-05-24T22:10:50+0000

Answer:

Area of the base of the pyramid will be
(3)/(2)x^(3) square inches.

Explanation:

The volume of a hexagonal pyramid is represented by the formula

V =
$(1)/(3)* (\text{area of the base}) * height$

Now it is given in the question, Volume v = 12x³ cubic inches

Height of the pyramid h = 24 inches

Now we plug in the values in the formula

12x³ =
$(1)/(3)(\text{Area of the base})(24)$

12x³ = Area of the base × 8

Area of the base =
(12x^(3) )/(8)

=
(3x^(3))/(2)

Therefore, area of the base of the pyramid is
(3)/(2)x^(3) square inches.