Answer:
Area of the base of the pyramid will be
square inches.
Explanation:
The volume of a hexagonal pyramid is represented by the formula
V =
![(1)/(3)* (\text{area of the base}) * height](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lxotn9uf2qizy3asf4ao9qfrtl2nb34ajs.png)
Now it is given in the question, Volume v = 12x³ cubic inches
Height of the pyramid h = 24 inches
Now we plug in the values in the formula
12x³ =
![(1)/(3)(\text{Area of the base})(24)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rwqpsrkmcw9igtysmm0ggtrb1v982s618c.png)
12x³ = Area of the base × 8
Area of the base =
![(12x^(3) )/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ia33y0c8hjy00if01j51t62k58i76cgt9d.png)
=
![(3x^(3))/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/moiqw1bevvqkc2twwcrmfggjsj59t4rx4r.png)
Therefore, area of the base of the pyramid is
square inches.