Question

hich function has a range of y? f(x) = (x – 4)2 + 5 f(x) = –(x – 4)2 + 5 f(x) = (x – 5)2 + 4 f(x) = –(x – 5)2 + 4

Answer 1

`f(x)=-(x-4)^2+5`

Explanation:

The function
`f(x)=-(x-4)^2+5` has the vertex at
`(4,5)`.

Since
`a=-1\:<\:0`, the graph of the function is a maximum graph.

The highest y-value is the y-coordinate of the vertex which is 5.

Therefore the range is {
`y|y\le 5`}

Therefore the correct answer is B.