Question

On the graph of f(x)=sinx and the interval [−2π,0), for what value of x does the graph cross the x-axis? Choose all answers that apply.

Select all that apply:

−2π
−3π2
−π
−π2
−π4

Answer 1

Correct answer:

−2π

−π

Explanation:

If we look at the graph of f(x)=sinx over [−2π,0), we see that the graph crosses the x- axis in two spots; x=−2π and x=−π. We do not include x=0 because we are looking at f(x)=sinx from −2π up to but not including 0..

Answer 2

The graph cross the x-axis at the points

−2π

−π

How to find the points

The points where the graph cuts the x-axis can be solved algebraically.

However, plotting the equation, f(x) = sine x on graph and monitoring the interval [−2π, 0), to notice where the graph intersects the x-axis will be used

From the graph, the points are −2π and −π