Quadratic linear and constant term of f(x)=(3x-6)(-4x+2)

Question

asked Nov 19, 2020 155k views

1 Answer

Bigkm · Answer 1 · 2020-11-26T19:58:42+0000

Answer:

It is quadratic.

The constant term is:-12

Explanation:

1. You can apply the Distributive Property of multiplication, as following:

$f(x)=(3x-6)(-4x+2)\\f(x)=(3x)(-4x)+(3x)(2)+(-6)(-4x)+(-6)(2)\\f(x)=-12x^(2)+6x+24x-12\\f(x)=12x^(2)+30x-12$

2. The function has the form:

f(x)=ax^(2)+bx+c

Therefore, it is a quadratic function, where
is the constant term.

3. Therefore, the constant term is -12