Answer:
The measure of angle YUV is equal to
![m<YUV=42\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iqbiay9tiqhqk3kmz5oj912gmih2ipt1yp.png)
Explanation:
see the attached figure to better understand the problem
we have that
-----> given problem
so
------> by central angle
we know that
The triangle UZV is an isosceles triangle
because
![ZU=ZV=radius](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kwngp37dkow6wlszuwkef4ada54a8i3h6l.png)
so
-----> bases angle of the isosceles triangle
Remember that
The sum of the internal angles of a triangle is equal to
![180\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bitigss8afocdjn4qvbzqw3vaxu5fqclwr.png)
so
![m<ZUV+m<ZVU+m<UZV=180\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xph7asw2i8s6v5sqx69a7id9u9l66drirk.png)
![2m<ZUV+m<UZV=180\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uujgk5t55oyp2yeu5nyneq7m8j314gw32y.png)
substitute and solve for m<ZUV
![2m<ZUV+84\°=180\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1iake6oc1a7zmdch1bmwnbr15dofzdxq15.png)
![m<ZUV=(180\°-84\°)/2=48\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7ynslpfokki486qbkznvk7kpxhplqbiall.png)
------> by complementary angles
solve for m<YUZ
![48\°+m<YUV=90\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g96ov6z81gin433ur52qi5pz43zbnaaq8v.png)
![m<YUV=90\°-48\°=42\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kkolfpjm8sazsd0cxgvtdv5btalgrzr6jp.png)