If f(x)=x over 2-3 and g(x)=3x^2+x-6 find (f+g)(x)

Question

asked Jun 15, 2020 135k views

2 Answers

Jrib · Answer 1 · 2020-06-16T11:08:10+0000

Answer:

(f + g) (x) =3x^(2) +(3)/(2)x-9

Explanation:

We are given the following two functions and we are to add them:

$f (x) = \frac {x} {2} -3$

g (x) = 3x^(2) + x - 6

Adding these two functions, we get:

(f + g) (x) = f (x) + g (x)

$(f + g) (x) = \frac {1} {2} x - 3 + 3x^(2) + x - 6$

Adding the like terms together and simplifying them to get:

$(f + g) (x) = 3x^(2) + \frac {3}{2} x - 9$

CBaker · Answer 2 · 2020-06-20T16:31:51+0000

Answer:

Explanation:

We are asked to find (f + g) (x)

In this case what we must do is add the function f (x) with the function g (x). So, we have:

$f(x) = (1)/(2)x - 3\\g (x) = 3x ^ 2 + x - 6\\(f + g) (x) = f(x) + g (x)\\(f + g) (x) = (1)/(2)x - 3 + 3x ^ 2 + x - 6$

Finally we simplify, and we have left:

(f + g)(x) = 3x ^ 2 + (3)/(2)x - 9