Question

If the velocity of gas molecules is doubled, then it’s kinetic energy will?( hint formula for kinetic energy is KE=.5 x mv2)

A stay the same

B double

C triple

D quadruple

Answer 1

D quadruple

Step-by-step explanation:

`E = (1)/(2)mv^2\\E'=(1)/(2)m(2v)^2=(1)/(2)m4 v^2 = 4((1)/(2)mv^2)=4E`

Answer 2

(D) quadruple

Step-by-step explanation:

`KE_(1) = (1)/(2)m v^(2)` -----equation 1

where;

KE₁ is the initial kinetic energy

m is the gas molecule mass

v is the velocity of gas molecules

⇒ When the velocity of gas molecules is doubled (2v)

`KE_(2) = (1)/(2)m (2v)^(2)`

`KE_(2) = (1)/(2)m*4v^(2)`

`KE_(2) = 4((1)/(2)mv^2)` -------equation 2

Recall; From equation 1;

`KE_(1) = (1)/(2)m v^(2)`

Substitute in KE₁ in equation 2

KE₂ = 4(KE₁)

Therefore, the kinetic energy will quadruple