Answer:
Explanation:
Given that Elijah threw a ball from a height of 4 feet. The ball reached maximum height of 16 feet after 2seconds
Let vertical component of his speed be v
When it reaches maximum height its velocity becomes 0
Hence
height reached by the ball =
![h=vt-(gt^2)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/v8sm6fix4rmpylrgyw614avfrhmfnilm9w.png)
When h=12(16-4) we get g=gravity =32
Hence 12 =2v-16(4)
v=38
Hence
![h=38t-(32t^2)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/nn4h643755oafi85b22pdnk2xwhn0ded0a.png)
where h is calculated from the height of hand i.e. 4 feet
When it touches the ground h =-4
When it starts falling then distance travelled = 16 feet
Initial velocity =0 Accn due to gracity =32 feet
Using these we can write
![16=0+(32t^2)/(2)\\ t=1](https://img.qammunity.org/2020/formulas/mathematics/high-school/yd0m87fveqs22envlw9rqulry9ehb8q9jr.png)
So after 3 minutes from start the ball would reach the ground