1) 0.1 kWh
Step-by-step explanation:
The power of the lightbulb is:
![P = 100 W=0.1 kW](https://img.qammunity.org/2020/formulas/physics/high-school/uzu7s57t9xspd6gxma4qmhg6xpegszp04a.png)
The energy used by the lightbulb is equal to the product between the power (P) and the time (t):
![E=Pt](https://img.qammunity.org/2020/formulas/physics/high-school/j5vnpc5avoair04lmif0fe9zbq8pft00dl.png)
Since the bulb has been left on for t = 1 h, the total electrical energy used is
![E=Pt=(0.1 kW)(1 h)=0.1 kWh](https://img.qammunity.org/2020/formulas/physics/high-school/uy7mc3ibpn1mmrj9smkdgvv76sbkwff9ah.png)
2) $ 0.018
Step-by-step explanation:
The company charges $0.18 per each kilowatt-hour. So, we can find the total cost charged for using 0.1 kWh of electricity by setting the following proportion:
$0.18 : 1 kWh = x : 0.1 kWh
And solving for x, we find
![x=(\$0.18 \cdot 0.1kWh)/(1 kWh)=\$ 0.018](https://img.qammunity.org/2020/formulas/physics/high-school/2n55csnykp1dvxcc3upzc3hq0pgt6zatsf.png)