Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Enter a recursive rule for the geometric sequence.

6, − 18, 54, − 162, ...

Answer 1

6 and -3a_n-1

Explanation:

took the test

Answer 2

Answer:
`\bold{a_1=6,\quad a_n=-3a_(n-1)}`

Explanation:

The recursive rule for a general geometric sequence is:
`a_n=a_(n-1)(r)\quad \text{where}\ a_(n-1)\ \text{is the previous term and r is the ratio}`

Given the sequence {6. -18, 54, -162, ... }, we can see that

• 
  `\text{the first term}\ (a_1)\ \text{is 6}`
• 
  `\text{the common ratio (r) is:}\ (-18)/(6)=-3`

So, the recursive rule is:
`a_n=-3a_(n-1)`