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Write the slope intercept form of the equation that passes through the point (-2,3) and is parallel to the line y= -6x -9

Y=-6 - 9
Y=-6 - 1
Y=6x - 9
Y=1/6x - 1

1 Answer

5 votes

Answer:

y = -6x -9

Explanation:

Slope intercept form: y=mx + b

Point slope form: y-y1 = m(x-x1)

The slope is -6

So, plug in the slope for m and (-2,3) for x and y.

y-3 = -6(x-(-2)

or

y - 3 = -6(x + 2)

Now distribute,

y - 3 = -6x - 12

Simplify by isolating y and adding 3 to both sides of the equation

y - 3 = -6x - 12

+3 + 3

y = -6x - 9

This is now in slope intercept form y = mx + b



User Ggarber
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