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Solve for x in the equation x² -8x + 41 = 0

1 Answer

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Answer:

x=4+5i and x=4-5i

Explanation:


x^2-8x + 41 = 0

we apply quadratic formula to solve for x


x=(-b+-√(b^2-4ac))/(2a)

a= 1, b= -8 and c= 41

Plug in all the values in the formula


x=(-b+-√(b^2-4ac))/(2a)


x=(-(-8)+-√((-8)^2-4(1)(41)))/(2(1))


x=(8+-√(64-164))/(2)


x=(8+-√(-100))/(2)

square root (-1) is 'i'


x=(8+-10i)/(2)

Divide both terms by 2

x= 4+-5i

two values of x are 4+5i and 4-5i



User Kevin Verstraete
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