Question

Listed below are amounts​ (in millions of​ dollars) collected from parking meters by a security company in a certain city. A larger data set was used to convict 5 members of the company of grand larceny. Find the mean and median for each of the two samples and then compare the two sets of results. Do the limited data listed here show evidence of stealing by the security​ company's employees?

Security​ Company:


1.4

1.1

1.4

1.1

1.8

1.2

1.6

1.2

1.2

1.3


Other​ Companies:


1.9

1.7

2.1

2.3

2.1

1.8

1.7

2.3

2.3

2.2


Find the means.


The mean for the security company is ​___ million and the mean for the other companies is ​____.

Answer 1

Security: mean = 1.33 and median is 1.25

Others : mean = 2.04 median is 2.1

Explanation:

Security Company

The mean is add up all the points and divide by the number of points

There are 10 points

mean = (1.4+1.1+1.4 +1.1+1.8+1.2+1.6+1.2+1.2+1.3)/10 =13.3/10 = 1.33

The median is the middle point after lining them up in order from smallest to largest

1.1,1.1,1.2,1.2,1.2,1,3,1.4,1.4 ,1.6,1.8

We need to add the 5th and 6th numbers and divide by 2

1.2+1.3 = 2.5

2.5/2 = 1.25

Mean = 1.33

Median = 1.25

Other companies

The mean is add up all the points and divide by the number of points

There are 10 points

Mean = (1.9+1.7+2.1+2.3+2.1+1.8+1.7+2.3+2.3+2.2) /10=20.4/10 = 2.04

The median is the middle point after lining them up in order from smallest to largest

1.7,1.7,1.8,1.9,2.1,2.1,2.2,2.3,2.3,2.3

We need to add the 5th and 6th numbers and divide by 2

Since it is the same number the mean will be that number

2.1