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Write the point-slope form of the equation with the given characteristics.

1. Slope =2, y-intercept =3

2. Slope = -2, passes through (-3,5)

3. parallel to the line y=3/5x -8, passes through (0,3)

4. perpendicular to the line y=-2x-7, passes through (-3,10)

User HBrent
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1 Answer

7 votes

Answer:

1. y = 2x+3

2. y= -2x-1

3. y=3/5 x +3

4. y = 1/2 x 23/2

Explanation:

1. Use slope intercept, y=mx+b where m =2 and b=3. y=2x+3

2. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-5)=-2(x--3)

y-5=-2(x+3)

y=-2x-6+5

y=-2x-1

3. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope is 3/5 since parallel lines have the same slope.

(y-3)=3/5(x-0)

y-3=3/5 x

y=3/5 x +3

4. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope is 1/2 since perpendicular lines have the negative reciprocal slopes. So -2 becomes 1/2.

(y-10)=1/2(x--3)

y-10=1/2 (x+3)

y-10 = 1/2 x + 3/2

y = 1/2 x 23/2



User Arcsector
by
6.9k points
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