73.9k views
4 votes
Help me please!!?!?? ?

Help me please!!?!?? ?-example-1
User Fefux
by
8.0k points

1 Answer

4 votes

1


3x^2 + 5y^2 - 12x + 30y + 42 = 0


3x^2 - 12x + 5y^2 + 30y = - 42


3(x^2 - 4x) + 5(y^2 + 6y) = -42


3(x^2 -4x + 4) + 5(y^2 + 6y + 9) = -42 + 12 + 45


3(x-2)^2 + 5(y+3)^2 = 15


((x-2)^2)/(5) + ((y+3)^2)/(3) = 1

Ellipse, same signs different coefficients on
x^2 and
y^2

2


9x^2 -36x - 4y^2 + 8y = 4


9(x^2 - 4x + 4) - 4(y^2 - 2y + 1) = 4 + 36 - 4


9(x- 2)^2 - 4(y - 1^2) = 36

Hyperbola, opposite signs on
x^2 and
y^2

3


y = x^2 +2x + 3 = (x + 1)^2 + 2

parabola

4


x^2 - 4 x + y^2 + 4y = 4


(x - 2)^2 + (y+2)^2 = 4 + 4 + 4 = 12

equal coefficents on
x^2 and
y^2, circle

5


-9x^2 - 18x + 4y^2 - 8y = 41


-9(x^2 -2x + 1) + 4(y^2 - 2y + 1) = 41 - 9 + 4


-9(x-1)^2 + 4(y-1)^2 = 36

hyperbola, opposite signs

6


-4x = y^2 - 2y - 11 = (y-1)^2 - 12

That's a parabola, sideways open to the left

7


2(x^2 + 6x) + 3(y^2 - 8y) = -60


2(x^2 + 6x + 9) + 3(y^2 - 8y + 16) = -60 + 18 + 48


2(x+3)^2 + 3(y - 4)^2 = 6


((x+3)^2)/(3) + ((y-4)^2)/(2) = 1

Ellipse, different coefficients

8


16x^2 - 32x - y^2 - 6y = 57


16(x^2 - 2x + 1) - (y^2 + 6y + 9) = 57 + 16 - 9 = 64

opposite signs, hyperbola

You'll have to do the graphing yourself, sorry


User Ben Zifkin
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories