Question

What are all the real zeros

Answer 1

For this case we have a function of the form
`y = f (x)`, where
`f (x) = (x-12) ^ 3-10`

To find the real zeros we must equal zero and clear the variable "x".

`(x-12) ^ 3-10 = 0`

We add 10 to both sides of the equation

`(x-12) ^ 3-10 + 10 = 10\\(x-12) ^ 3 = 10`

We apply cube root to both sides of the equation:

`\sqrt[3]{(x-12)^3} = \sqrt[3] {10}\\x-12 = \sqrt[3] {10}`

We add 12 to both sides of the equation:

`x-12 + 12 = \sqrt[3] {10} +12\\x = \sqrt[3] {10} +12`

Answer:

Option D