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((Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

((Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!-example-1
User Ahmer Khan
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1 Answer

2 votes

Answer:

This series is divergent

B.

Explanation:

We are given a series

Firstly, we will find nth term

Numerator:

2 , 4, 8 , 16 , .....


a_n=2^n

Denominator:

1^2 , 2^2 , 3^2 , ....


b_n=n^2

now, we can find nth term


c_n=(2^n)/(n^2)

We can use ratio test


L= \lim_(n \to \infty) c_n= \lim_(n \to \infty) ((2^(n+1))/((n+1)^2))/((2^n)/(n^2))


L=\lim _(n\to \infty \:)\left((2n^2)/(\left(n+1\right)^2)\right)


L=2\left(\lim _(n\to \infty \:)\left((1)/(1+(1)/(n))\right)\right)^2


L=2\left((1)/(1)\right)^2


L=2>1

Since, it is greater than 1

so, this series is divergent

User AJ Dhaliwal
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7.9k points