93.7k views
3 votes
((Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

((Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!-example-1
User Ahmer Khan
by
7.9k points

1 Answer

2 votes

Answer:

This series is divergent

B.

Explanation:

We are given a series

Firstly, we will find nth term

Numerator:

2 , 4, 8 , 16 , .....


a_n=2^n

Denominator:

1^2 , 2^2 , 3^2 , ....


b_n=n^2

now, we can find nth term


c_n=(2^n)/(n^2)

We can use ratio test


L= \lim_(n \to \infty) c_n= \lim_(n \to \infty) ((2^(n+1))/((n+1)^2))/((2^n)/(n^2))


L=\lim _(n\to \infty \:)\left((2n^2)/(\left(n+1\right)^2)\right)


L=2\left(\lim _(n\to \infty \:)\left((1)/(1+(1)/(n))\right)\right)^2


L=2\left((1)/(1)\right)^2


L=2>1

Since, it is greater than 1

so, this series is divergent

User AJ Dhaliwal
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories