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21 votes
21 votes
Help meeeeeee please​

Help meeeeeee please​-example-1
User Lazy
by
3.1k points

1 Answer

10 votes
10 votes
Answer: 4/9

Possible number of pairs given cards:
3*3=9

Number of sum with odd score, two odd numbers added to an even number from each box:
2*1+1*2=4 (pairs of 3 and 5 with 2 or pairs of 9 and 3 with 4)

Required probability:
P(odd)=4/9
User Benkiefer
by
4.2k points