Question

PLZ HELP WITH THIS QUESTION PLZ CORRECT ANSWERS!!! LOVE YOU THNX

oh and its just 2 question for 30 points!!

Answer 1

1) The value of x= 0.0642

2)
`sin\theta=(P)/(H)=(24)/(25)`

`cos\theta=(B)/(H)=(7)/(25)`

`tan\theta=(P)/(B)=(24)/(7)`

`cosec\theta=(H)/(P)=(25)/(24)`

`cot\theta=(B)/(P)=(7)/(25)`

Explanation:

1) Given : A right angle triangle with sides x and 10 and angle is 50°

To find : Value of x

Solution : Since, it is a right angle triangle

Therefore, we apply
`cos\theta=(B)/(H)`

Where Base = x, Hypotenuse= 10, angle = 50°

`cos(50)=(x)/(10)`

`0.642=(x)/(10)`

`0.0642=x`

The value of x= 0.0642

2) Given :
`sec\theta=(25)/(7)`

To find : Value of
`sin\theta,cos\theta,tan\theta,cosec\theta,cot\theta`

Solution : We have given
`sec\theta=(25)/(7)`

`sec\theta=(H)/(B)`

so, B= 7 , H=25

By Pythagoras theorem,

`H^2=P^2+B^2`

`25^2=P^2+7^2`

`625-49=P^2`

`√(576)=P^2`

`P=24`

Now, P=24, B=7, H=25

`sin\theta=(P)/(H)=(24)/(25)`

`cos\theta=(B)/(H)=(7)/(25)`

`tan\theta=(P)/(B)=(24)/(7)`

`cosec\theta=(H)/(P)=(25)/(24)`

`cot\theta=(B)/(P)=(7)/(25)`