Answer:
∠ADB=35°
Explanation:
Given arc AB = 70°.
we have to find the angle ∠ADB
Here, Angle subtended by arc AB at O is ∠AOB = 70°
By the theorem,
The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
∴ ∠AOB=2(∠ADB)
⇒
![\angle ADB=(1)/(2)\angle AOB=(1)/(2)70^(\circ)= 35^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/high-school/z4eqezr78ywtyjo8ih4mo60lre9j2hjlpd.png)
hence, angle subtended at the circumference is 35°