Question

Factor completely 3x4y3 − 15x2y2 + 6xy.

3xy(x3y2 − 5xy + 2)
3x(x3y3 − 5xy2 + 2y)
3(x4y3 − 5x2y2 + 2xy)
Prime

Answer 1

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factor 3x^4y^3 − 15x^2y^2 + 6xy

to Wolfram Alpha.

3xy(x^3y^2 − 5xy + 2) is the "irreducible factorization".

Answer 2

option A. 3xy(x³y² - 5xy + 2)

Explanation:

The given expression is 3x⁴y³ - 15x²y² + 6xy

We have to factor the expression completely

3x⁴y³ - 15x²y² + 6xy

3xy [ x³y² - 5xy + 2 ]

Therefore, the factored form of the given expression is option A. 3xy(x³y² - 5xy + 2)