What is the density of iron if 5.0 cm3 has a mass of 39.5g

asked Apr 9, 2020 62.5k views

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Answer :
$\rho = 7.9\ g/cm^3$

Step-by-step explanation :

It is given that

Mass of iron, m = 39.5 g

Volume of iron,
$V = 5\ cm^3$

So, density is :

density,
$\rho =(mass)/(volume)$

$\rho =(39.5g)/(5cm^3)$

$\rho = 7.9\ g/cm^3$

Nwaxgui answered Apr 16, 2020

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