Question

About 5.67811 X10^5 liters of water flow over Niagara Falls per second there are 3.15576 x10^7 seconds in one year the number of liters of water that flows over Niagara Falls each year are about 5.67811 x 10^5 x3.15476x10^7

A.1e12
B. 179187524.1
C.1.791875241e13
D. 1.92559524e-44

Answer 1

Answer: C. 1.7918752e+13

Explanation:

Since, water flow over Niagara Falls per second =
`5.67811 * 10^5`

In one year, the number of seconds =
`3.15576 * 10^7`

Thus, the total quantity of water flows over Niagara Falls each year

=
`5.67811 * 10^5 * 3.15476* 10^7`

=
`1.7918752* 10^(13)`

=
`1.7918752e13`

⇒ Option C is correct.