Question

Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of

z0 = -1 - 2i.


a.
1 - 6i, 5 - 14i, 13 - 30i
c.
5 - 2i, 13 - 2i, 29 - 2i
b.
2 - 5i, 9 - 17i, 21 - 37i
d.
3 - 2i, 17 - 2i, 23 - 2i

Answer 1

Answer: a

Explanation:

`z_0=-1-2i\\\\z_1=2(-1-2i)+(3-2i)=-2-4i+3-2i=1-6i`

This eliminates all the options except for a.