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What is an equation of the line perpendicular to y=-2x-2 and through (-2,4)

User KVM
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Let
k:y=m_1x+b_1 and
l:y=m_2x+b_2


l\ \perp\ k\iff m_1m_2=-1\to m_2=-(1)/(m_1)

We have


y=-2x-2\to m_1=-2

Therefore


m_2=-(1)/(-2)=(1)/(2)

We have the equation of a line:


y=(1)/(2)x+b

Put the coordinates of the point (-2, 4) to the equation of a line:


4=(1)/(2)(-2)+b


4=-1+b add 1 to both sides


5=b\to b=5

Answer:
\boxed{y=(1)/(2)x+5}

User Jimmy Engelbrecht
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